wuyamao 最近的时间轴更新 wuyamao 最近的时间轴更新 | wuyamaoV2EX 第 310496 号会员，加入于 2018-04-21 21:03:07 +08:00 |
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2021-01-16 01:02:09 +08:00 回复了 dwadewyp 创建的主题 Python 这道逻辑题 用 Python 代码 如何实现? |
if Ans1 == 1 or (Ans1==2 and Ans2==1) or (Ans1==3 and Ans2!=1 and Ans3==1) or (Ans1==4 and Ans2!=1 and Ans3!=1 and Ans1==1):
if (Ans2 == 1 and Ans5==Ans6 and Ans1 != Ans2 and Ans2 != Ans3 and Ans3 != Ans4 and Ans4 != Ans5 and Ans6 != Ans7 and Ans7 != Ans8 and Ans8 != Ans9 and Ans9 != Ans10) or (Ans2 == 2 and Ans6==Ans7 and Ans1 != Ans2 and Ans2 != Ans3 and Ans3 != Ans4 and Ans4 != Ans5 and Ans5 != Ans6 and Ans7 != Ans8 and Ans8 != Ans9 and Ans9 != Ans10) or (Ans2 == 3 and Ans8==Ans7 and Ans1 != Ans2 and Ans2 != Ans3 and Ans3 != Ans4 and Ans4 != Ans5 and Ans6 != Ans7 and Ans5 != Ans6 and Ans8 != Ans9 and Ans9 != Ans10) or (Ans2 == 4 and Ans8==Ans9 and Ans1 != Ans2 and Ans2 != Ans3 and Ans3 != Ans4 and Ans4 != Ans5 and Ans6 != Ans7 and Ans5 != Ans6 and Ans9 != Ans10):
if (Ans3 == 1 and Ans4==1) or (Ans3 == 2 and Ans9==2) or (Ans3 == 3 and Ans8==3)or (Ans3 == 4 and Ans2==4):
countA = count(1,Ans1,Ans2,Ans3,Ans4,Ans5,Ans6,Ans7,Ans8,Ans9,Ans10)
if (Ans4 == 3 and countA == 3 ) or (Ans4 == 4 and countA ==2 ):
if (Ans5 == 1 and Ans1==1) or (Ans5 == 2 and Ans2==2) or (Ans5 == 3 and Ans3==3)or (Ans5 == 4 and Ans4==4):
countB = count(2,Ans1,Ans2,Ans3,Ans4,Ans5,Ans6,Ans7,Ans8,Ans9,Ans10)
countC = count(3,Ans1,Ans2,Ans3,Ans4,Ans5,Ans6,Ans7,Ans8,Ans9,Ans10)
countD = count(4,Ans1,Ans2,Ans3,Ans4,Ans5,Ans6,Ans7,Ans8,Ans9,Ans10)
if (Ans6 == 1 and countA != countB and countA != countC and countA != countD) or (Ans6 == 2 and countA == countC and countA != countD) or (Ans6 == 3 and countA == countC and countA != countD) or (Ans6 == 4 and countA == countD and countA != countC):
if (Ans7 == 1 and abs(Ans7-Ans8)==3) or (Ans7 == 2 and abs(Ans7-Ans8)==2) or (Ans7 == 3 and abs(Ans7-Ans8)==1)or (Ans7 == 4 and Ans8==4):
if (Ans8 == 3 and Ans4 == 4) or (Ans8 == 4 and Ans4 == 3):
countBCD = 10 - countA
if (Ans9==1 and (countBCD in [6,8])) or (Ans9==2 and (countBCD in [5,7])) or (Ans9==4 and countBCD ==9 ):
自己排版吧,可能有些有点漏
if (Ans2 == 1 and Ans5==Ans6 and Ans1 != Ans2 and Ans2 != Ans3 and Ans3 != Ans4 and Ans4 != Ans5 and Ans6 != Ans7 and Ans7 != Ans8 and Ans8 != Ans9 and Ans9 != Ans10) or (Ans2 == 2 and Ans6==Ans7 and Ans1 != Ans2 and Ans2 != Ans3 and Ans3 != Ans4 and Ans4 != Ans5 and Ans5 != Ans6 and Ans7 != Ans8 and Ans8 != Ans9 and Ans9 != Ans10) or (Ans2 == 3 and Ans8==Ans7 and Ans1 != Ans2 and Ans2 != Ans3 and Ans3 != Ans4 and Ans4 != Ans5 and Ans6 != Ans7 and Ans5 != Ans6 and Ans8 != Ans9 and Ans9 != Ans10) or (Ans2 == 4 and Ans8==Ans9 and Ans1 != Ans2 and Ans2 != Ans3 and Ans3 != Ans4 and Ans4 != Ans5 and Ans6 != Ans7 and Ans5 != Ans6 and Ans9 != Ans10):
if (Ans3 == 1 and Ans4==1) or (Ans3 == 2 and Ans9==2) or (Ans3 == 3 and Ans8==3)or (Ans3 == 4 and Ans2==4):
countA = count(1,Ans1,Ans2,Ans3,Ans4,Ans5,Ans6,Ans7,Ans8,Ans9,Ans10)
if (Ans4 == 3 and countA == 3 ) or (Ans4 == 4 and countA ==2 ):
if (Ans5 == 1 and Ans1==1) or (Ans5 == 2 and Ans2==2) or (Ans5 == 3 and Ans3==3)or (Ans5 == 4 and Ans4==4):
countB = count(2,Ans1,Ans2,Ans3,Ans4,Ans5,Ans6,Ans7,Ans8,Ans9,Ans10)
countC = count(3,Ans1,Ans2,Ans3,Ans4,Ans5,Ans6,Ans7,Ans8,Ans9,Ans10)
countD = count(4,Ans1,Ans2,Ans3,Ans4,Ans5,Ans6,Ans7,Ans8,Ans9,Ans10)
if (Ans6 == 1 and countA != countB and countA != countC and countA != countD) or (Ans6 == 2 and countA == countC and countA != countD) or (Ans6 == 3 and countA == countC and countA != countD) or (Ans6 == 4 and countA == countD and countA != countC):
if (Ans7 == 1 and abs(Ans7-Ans8)==3) or (Ans7 == 2 and abs(Ans7-Ans8)==2) or (Ans7 == 3 and abs(Ans7-Ans8)==1)or (Ans7 == 4 and Ans8==4):
if (Ans8 == 3 and Ans4 == 4) or (Ans8 == 4 and Ans4 == 3):
countBCD = 10 - countA
if (Ans9==1 and (countBCD in [6,8])) or (Ans9==2 and (countBCD in [5,7])) or (Ans9==4 and countBCD ==9 ):
自己排版吧,可能有些有点漏
2018-08-08 22:09:35 +08:00 回复了 twor 创建的主题 问与答 电信宽带是公网 ip，我映射 8888 到内网某 ubuntu 的 80 端口，公网访问成功；映射其他端口（2222， 8889）到 22（局域网是可以 ssh 的），为什么 ssh 登录不成功呢 |
电信光猫上有 iptables 防火墙,可能过滤了 22 端口,把 ssh 端口改成其他试试
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