一种实现如下：
test_tup = ('gfg', 1, ['is', 'best']) list(map(type, test_tup)) 该实现是获取元祖实例的每个元素的类型。
但如果只是类型，比如(str,)，还没赋值，怎么获取到里面的类型？
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This topic created in 1005 days ago, the information mentioned may be changed or developed.
 | 1 xe2vherd Aug 11, 2023 |
 | 2 coderluan Aug 11, 2023 python 里面，本来就是赋值之后变量才确定类型，楼主你想创建个对象确定类型但是不赋值，可以使用类型注释： from typing import Tuple, List test_tup: Tuple[str, int, List[str]] = ('gfg', 1, ['is', 'best']) |
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