shell 脚本的字符串中包含的变量要怎么才能被解析 - V2EX
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justRua

shell 脚本的字符串中包含的变量要怎么才能被解析

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  •   justRua May 25, 2022 1382 views
    This topic created in 1436 days ago, the information mentioned may be changed or developed.
    有个配置文件 file.properties ，里面有个配置项:
    opts=-Xmx1024m -Xms1024m -Djava.io.tmpdir=${TEMP_DIR}

    现在有个脚本 a.sh ，会读取这个 file.properties 获取到 opts 后面的内容赋值到变量 testParam 中。
    testParam 实际取到的值为-Xmx1024m -Xms1024m -Djava.io.tmpdir=${TEMP_DIR}

    现在问题是${TEMP_DIR} 在脚本中是有定义的，TEMP_DIR="./tmp"，
    期望是得到 testParam=-Xmx1024m -Xms1024m -Djava.io.tmpdir=./tmp

    请问各位彦祖这个要怎么实现~
  • temp_dir
  • xms1024m
  • xmx1024m
  • testparam
    3 replies    2022-05-25 18:53:16 +08:00
    AoEiuV020CN
        1
    AoEiuV020CN  
       May 25, 2022
    盲猜你需要 envsubst
    privil
        2
    privil  
       May 25, 2022
    eval 吧
    justRua
        3
    justRua  
    OP
       May 25, 2022
    @privil 谢谢啦，试了下确实可以，之前有想过用 eval ，但搜了下网上的例子用不了
    换了个姿势试了试可以了，eval_opts=`eval echo "$opts"`
    这样写$opts 中的${TEMP_DIR}会被解析到，此贴完结。。。
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