求助多线程方面的问题 - V2EX
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Rever1e
V2EX    Java

求助多线程方面的问题

  •  
  •   Rever1e 2020-12-30 19:42:01 +08:00 1937 次点击
    这是一个创建于 1795 天前的主题,其中的信息可能已经有所发展或是发生改变。

    ##目的:支线程接受 socket,打断主函数的输入

    支线程与主线程并行,支线程等待 Serversocket.accept(),主线程等待 Scanner.next().
    现在希望支线程接收 Socket 后,中断主线程输入,继续执行支线程之后内容

    图片

    ##目前

    主线程 支线程

    需要的是 lock.wait 在同步代码块外,但是这样语法错误
    如果在同步代码块中它一直执行主函数的等待输入

    ##主线程

    Server server = new Server(); server.initServer(LockServer); server.start(); synchronized (LockClick) { synchronized (LockServer){ while (true) { Menu.printMenu(); Menu.scan(LockClick,LockServer);//看作 Scanner.next() System.out.println("----------------"); } }} 

    ##支线程

    public void run(){ PrintWriter out=null; Scanner get = null; try { System.out.println("服务正在运行,等待客户端连接!"); log.write("点对点服务端开启"); while (true) { Socket client = server.accept(); //接收 socket,打断主线程输入 //lock.wait(); synchronized (lock) { lock.wait(); InetAddress inetAddress = client.getInetAddress(); 

    具体代码:https://github.com/0x00stone/chat/blob/master/src/Client1/mainThread.java https://github.com/0x00stone/chat/blob/master/src/Client1/Server.java

    1 条回复    2021-01-06 11:24:49 +08:00
    PUGE
        1
    PUGE  
       2021-01-06 11:24:49 +08:00
    wait ()必须放到 while 循环内,因为可能有虚假唤醒的可能,你这写法很容易死循环啊,推荐用 2 个 semaphore 来做,而且感觉你这需求有点不太对
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