Python 怎么获取多线程的总执行时间??

一个 多线程爬视频的 py 脚本,我想看下总的执行时间,求大佬帮忙看看???

 # -*- coding: utf-8 -*- # @Author : 徐敏 # @File : movie_multiple.py # @Project: python_spider # @CreateTime : 2020-06-22 10 # encoding utf-8 import requests from queue import Queue import threading import time start_total_time = 0 end_total_time = 0 # 创建线程 生产者负责获取 URL，并且解析 URL class Procuder(threading.Thread): def __init__(self, num_queue, ts_queue, *args, **kwargs): super(Procuder, self).__init__(*args, **kwargs) self.num_queue = num_queue self.ts_queue = ts_queue def run(self): while True: if self.num_queue.empty(): # 如果队列为空就，线程执行完成，跳出死循环，结束 run print("Procuder 队列为空") break url = self.num_queue.get() self.download_ts(url) def download_ts(self, url): r = requests.get(url) ret = r.content # 倒数 8 位,取到文件名 filename = url[-8:] self.ts_queue.put((ret, filename)) # 创建线程 消费者 负责下载 class Consumer(threading.Thread): def __init__(self, num_queue, ts_queue, *args, **kwargs): super(Consumer, self).__init__(*args, **kwargs) self.num_queue = num_queue self.ts_queue = ts_queue def run(self): while True: if self.ts_queue.empty() and self.num_queue.empty(): # 如果队列为空就，线程执行完成，跳出死循环，结束 run print("Consumer 队列为空") end_total_time = time.time() break start_time = time.time() ret, filename = self.ts_queue.get() # 将 ts 文件保存到文件夹里 with open('./mp4/{}'.format(filename), 'wb') as f: f.write(ret) end_time = time.time() print('{}下载完成!,耗时:{}'.format(filename,end_time - start_time) ) def main(): # 定义线程 num_queue = Queue(500) ts_queue = Queue(500) # 先自定义好总共爬取的数量 # for i in range(470): for i in range(30): url = " https://us8.wl-cdn.com/hls/20200619/e1c5cc36967e6dac688b5e9c4006a567/film_" + '{0:05d}'.format(i) + ".ts" num_queue.put(url) # time.sleep(1) # 定义生产者 for x in range(5): print("Procuder") t = Procuder(num_queue, ts_queue) t.start() # 定义消费者 for x in range(5): print("Consumer") t = Consumer(num_queue, ts_queue) t.start() if __name__ == '__main__': start_total_time = time.time() lock = threading.RLock() # 加锁 lock.acquire() try: main() finally: # 修改完成，释放锁 lock.release() print("完成下载,总耗时{}".format(end_total_time - start_total_time))