golang 字符串技巧分享(1)--分割

引

开发过程中少不了要于字符串打交道。假如要对一个文本串进行分段，分割符是.?;. 还要保留分割符号，就不能使用常用的 string.Split 函数，Split 会把分割符去除。下面介绍两种方式。

基于状态方法

用时 2:42

package main import ( "fmt" ) func main() { const input = "1,2,3,4,5;6.7?" var all []string prev := 0 for i := 0; i < len(input); i++ { switch input[i] { case ',', '.', ';', '?': all = append(all, input[prev:i+1]) prev = i + 1 } } for _, v := range all { fmt.Printf("%s\n", v) } } 

基于 scanner

用时 1:28(复制官网例子，修改回调函数的内容，所以用时很短)

package main import ( "bufio" "fmt" "os" "strings" ) func main() { // Comma-separated list; last entry is empty. const input = "1,2,3,4,5;6.7?" scanner := bufio.NewScanner(strings.NewReader(input)) // Define a split function that separates on commas. onComma := func(data []byte, atEOF bool) (advance int, token []byte, err error) { for i := 0; i < len(data); i++ { switch data[i] { case ',', '.', ';', '?': return i + 1, data[:i+1], nil } } if !atEOF { return 0, nil, nil } // There is one final token to be delivered, which may be the empty string. // Returning bufio.ErrFinalToken here tells Scan there are no more tokens after this // but does not trigger an error to be returned from Scan itself. return 0, data, bufio.ErrFinalToken } scanner.Split(onComma) // Scan. for scanner.Scan() { fmt.Printf("%q ", scanner.Text()) } if err := scanner.Err(); err != nil { fmt.Fprintln(os.Stderr, "reading input:", err) } } 

交流学习

上面两种方式都把编码时间写上，欢迎 v 贴出自己的方法，互相学习。

github

https://github.com/guonaihong/gout