这个该怎么分析 - V2EX

这个该怎么分析 - V2EX

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这是一个创建于 2282 天前的主题，其中的信息可能已经有所发展或是发生改变。

package main import "fmt" func main() { var a map[string]string fmt.Println(a == nil) f(a) } func f(in interface{}) { fmt.Println(in == nil) }

true false

1 条回复 2019-07-16 11:27:23 +08:00

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BCy66drFCvk1Ou87

2019-07-16 11:27:23 +08:00

go 中的 interface 包含 2 个指针，分别指向值的类型和实际的值。把一个 map[string]string 赋给 interface，interface 存了指向 string 类型的指针，因此不再是 nil。

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