var value = '1,2,3,4,5,6,7,8,9' 输出[2, 5, 8]
输出索引匹配 i%3===1 的整形数组
1 cyd 2019-05-24 15:36:47 +08:00 value.split(",").filter((i,j)=>j%3===1) |
![]() | 2 bdbd001 2019-06-12 10:54:33 +08:00 value.split(",").map((i)=>i*1).filter((i)=>(i%3===2)) |