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thisisgpy

关于一个正则表达式在 Java 里面匹配不到的奇怪问题

  •  
  •   thisisgpy Apr 30, 2019 2929 views
    This topic created in 2562 days ago, the information mentioned may be changed or developed.

    我需要匹配一行字符串里面所有的 ${} 占位符,使用的正则表达式为

    \$\{(.*?)\} 

    测试字符串为:

    hello, ${name}. Your level is ${level} 

    我用 OSChina 的在线正则表达式测试工具 http://tool.oschina.net/regex/ 进行测试,可以正确匹配到两个占位符。

    但是我在 Java 里面就不能匹配到。

    Pattern pattern = Pattern.compile("\\$\\{(.*?)\\}"); String test = "hello, ${name}. Your level is ${level}"; Matcher matcher = pattern.matcher(test); System.out.println(matcher.matches()); // 输出 false 

    求教这是怎么回事~~懵逼了一早上

    4 replies    2019-04-30 14:10:01 +08:00
    c4f36e5766583218
        1
    c4f36e5766583218  
       Apr 30, 2019
    http://tool.oschina.net/uploads/apidocs/jdk-zh/java/util/regex/Matcher.html#matches()
    当且仅当整个区域序列匹配此匹配器的模式时才返回 true。
    iffi
        2
    iffi  
       Apr 30, 2019
    这样子来
    ```public static void main(String[] args) {
    Pattern pattern = Pattern.compile("\\$\\{(.*?)\\}");
    String test = "hello, ${name}. Your level is ${level}";
    Matcher matcher = pattern.matcher(test);
    while (matcher.find()) {
    System.out.println(matcher.group());
    }
    }
    ```
    Defined     3
    Defined  
       Apr 30, 2019
    import java.util.regex.Matcher;
    import java.util.regex.Pattern;

    final String regex = "\\$\\{(.*?)\\}";
    final String string = "hello, ${name}. Your level is ${level}\n";

    final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
    final Matcher matcher = pattern.matcher(string);

    while (matcher.find()) {
    System.out.println("Full match: " + matcher.group(0));
    for (int i = 1; i <= matcher.groupCount(); i++) {
    System.out.println("Group " + i + ": " + matcher.group(i));
    }
    }
    mooncakejs
        4
    mooncakejs  
       Apr 30, 2019
    java 坑爹处就是 matches 从头匹配到尾
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