爬虫( Python )如何处理页面上的 加载 按钮? - V2EX
SharkIng

爬虫( Python )如何处理页面上的 加载 按钮?

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  •   SharkIng Mar 21, 2019 3376 views
    This topic created in 2614 days ago, the information mentioned may be changed or developed.

    https://www.taappliance.com/en/catalog/835-Kitchen/41-Refrigerators/b5-LG

    类似于这种网站,产品列表如何一次性显示全部? 访问的时候需要点击 Load More 才加载,但是用 python 之类的爬虫如何实现一次性加载全部呢?

    Supplement 1    Mar 26, 2019
    已经搞定了,谢谢大家
    10 replies    2019-03-26 01:20:18 +08:00
    lhx2008
        1
    lhx2008  
       Mar 21, 2019 via Android
    抓包,和普通分页没有区别
    niknik
        2
    niknik  
       Mar 21, 2019
    error1009
    Johnson66
        3
    Johnson66  
       Mar 21, 2019
    The owner of this website (www.taappliance.com) has banned the country or region your IP address is in (CN) from accessing this website.
    holajamc
        4
    holajamc  
       Mar 21, 2019   1
    wuyifar
        5
    wuyifar  
       Mar 21, 2019   1
    做不到一次性的,解析他的接口参数,直接自己去访问
    SleipniR
        6
    SleipniR  
       Mar 21, 2019   1
    一般是触发 ajax 请求并返回 json,F12 看一下请求的链接手动触发一下。
    showHand043
        7
    showHand043  
       Mar 22, 2019   1
    ghost 或者 selenium+phantomJS
    SharkIng
        8
    SharkIng  
    OP
       Mar 23, 2019
    @holajamc #4
    @wuyifar #5
    @SleipniR #6 发现这个情况了,但是有点不知道具体他需要什么参数得到结果
    holajamc
        9
    holajamc  
       Mar 23, 2019   1
    相关的 JS 在这里
    /html/body/div[1]/script[35]/text()
    可以看看~
    SharkIng
        10
    SharkIng  
    OP
       Mar 26, 2019
    @holajamc 好的谢谢
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