游戏中连胜场次数统计的问题, 求指教 - V2EX
slgz

游戏中连胜场次数统计的问题, 求指教

  •  
  •   slgz Jul 4, 2018 1936 views
    This topic created in 2874 days ago, the information mentioned may be changed or developed.

    需求:
    类似于游戏中的连胜, 就是比如你今天赢了两场, 然后没玩了, 第二天又赢两把了, 此时的连胜场次就应该为四场.如果, 输了连胜场次数从 0 开始.

    服务端 , (PHP):
    目前服务端只知道游戏桉树的人和赢的人.然后游戏是一分钟一把的,如果通过查询, 得要做很多逻辑代码的判断 速度非常慢.

    客户端:
    如果是输了, 客户端没有做回调,如果要做, 必须强制更新客户端(PASS)

    所以, 想请问有好的做法吗?

    4 replies    2018-07-05 09:17:40 +08:00
    imn1
        1
    imn1  
       Jul 4, 2018
    不用登陆?匿名游戏?
    night98
        2
    night98  
       Jul 4, 2018
    加个单独的字段啊,赢一把+1,输了置 0.
    icebay
        3
    icebay  
       Jul 4, 2018
    单独维护一个字段咯。
    slgz
        4
    slgz  
    OP
       Jul 5, 2018
    @night98
    @IceBay 说了呀, 输的话我只能自己去通过玩的和赢的人去匹配. 无法直接得知他是输是赢
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