
if A1: if A2 == X2: if B1: if B2 == Y2: do_something() else: print 'B2 must equal to Y2' else: do_something() else: print 'A2 must equal to X2' elif B1: if B2 == Y2: do_something() else: print 'B2 must equal to Y2' else: print 'Choose at least one between A1 and B1' 1 pktangyue 2018-04-26 16:36:22 +08:00 if not A1 and not B1: print 'Choose at least one between A1 and B1' return if A1 and A2 != X2: print 'A2 must equal to X2' return if B1 and B2 != Y2: print 'B2 must equal to Y2' return do_something() |
2 xmadi 2018-04-26 16:41:11 +08:00 via iPhone 。。。。 这个和语法没有关系了 纯粹是逻辑归纳能力不行 |