比如说，我有一个 list
>>> l = [2, 3, 4, 5, 2, 3, 4, 2, 6, 4, 3] 我还有一个函数
>>> fn = lambda x: x%2 我想根据把 l 的每个元素作用到函数 fn 上
根据其返回值分类
>>> SOME_FUNCTION(fn, l) { 0: [2, 4, 2, 4, 2, 6, 4], 1: [3, 5, 3, 3] } 有这种工具吗? (虽然写一个也不麻烦)
感谢
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This topic created in 3188 days ago, the information mentioned may be changed or developed.
 | 1 newlife Sep 8, 2017 没有 |
 | 2 lishunan246 Sep 8, 2017 d = {} for x in l: r = f(x) if r in d: d[r].append(x) else: d[r] = [x] 这样？ |
 | 3 aheadlead OP @lishunan246 . def classify(classifier, container): . ret = defaultdict(list) . for i in container: . ret[classifier(i)].append(i) . return ret |
 | 4 guyskk Sep 8, 2017 via Android  1 itertools.groupby |
 | 5 NoAnyLove Sep 8, 2017 1 听你的需求像是 itertools.groupby，但是 group 要求先对数据进行 sort，不然会产生多组相同 key 的结果 |
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