请教下 js 的这种 for 循环语法怎么改写成 Python 的 - V2EX
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61882328

请教下 js 的这种 for 循环语法怎么改写成 Python 的

  •  
  •   61882328 May 31, 2017 4237 views
    This topic created in 3269 days ago, the information mentioned may be changed or developed.

    python 有下面这段 js 的写法吗?

     for ( d = Math.floor(k.length / 5), e = parseInt(k.charAt(d) + k.charAt(2 * d) + k.charAt(3 * d) + k.charAt(4 * d) + k.charAt5 * d)), f = Math.round(b.length / 2), g = Math.pow(2, 31) - 1, h = parseInt(a.substring(a.length - 8, a.length), 16), a = a.substring(0, a.length - 8), k += h; k.length > 10;) { k = (parseInt(k.substring(0, 10)) + parseInt(k.substring(10, k.length))).toString(); } 
    7 replies    2017-06-01 15:44:31 +08:00
    misaka19000
        1
    misaka19000  
       May 31, 2017 via Android
    写一下不就知道了,我感觉应该是有的
    fszaer
        2
    fszaer  
       May 31, 2017
    问题只在于把变量声明写在了 for 里而已吧
    ```js
    const d = Math.floor(k.length / 5),
    e = parseInt(k.charAt(d) + k.charAt(2 * d) + k.charAt(3 * d) + k.charAt(4 * d) + k.charAt(5 * d)),
    f = Math.round(b.length / 2),
    g = Math.pow(2, 31) - 1,
    h = parseInt(a.substring(a.length - 8, a.length), 16),
    a = a.substring(0, a.length - 8);

    for (k += h; k.length > 10;) {

    k = (parseInt(k.substring(0, 10)) + parseInt(k.substring(10, k.length))).toString();

    }


    ```

    把它们都提出来的话,不就是一个十分普通的 for 循环而已么?
    61882328
        3
    61882328  
    OP
       May 31, 2017
    @fszaer 明白了
    SoloCompany
        4
    SoloCompany  
       Jun 1, 2017
    这个循环有毒吧,声明了一堆的全局变量出来,或者你只是把混淆的代码前面的那一堆 var 声明给遮住了?
    Rice
        5
    Rice  
       Jun 1, 2017
    这是代码混淆后的结果?
    ibufu
        6
    ibufu  
       Jun 1, 2017
    这代码有毒,正常人谁会这么写代码
    crashX
        7
    crashX  
       Jun 1, 2017
    也就 es6 之前的垃圾语法能这么写,除了 js 没谁了。
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