用 python 写的判断质数的程序,输入一个较大的奇数时它告诉我可以被 2 整除,为什么? - V2EX
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Bill1

用 python 写的判断质数的程序,输入一个较大的奇数时它告诉我可以被 2 整除,为什么?

  •  
  •   Bill1 Jan 7, 2017 3088 views
    This topic created in 3421 days ago, the information mentioned may be changed or developed.

    程序代码如下:

    print("To determine whether the prime number") primenumbertext=input("Enter a number:") primenumber=float(primenumbertext) testnumber=2 while True: if testnumber==primenumber: print(primenumbertext+" is prime number!") input() break elif primenumber%testnumber==0: testnumbertext=str(testnumber) print(primenumbertext+" can be divisible by "+testnumbertext+" !") input() break testnumber=testnumber+1 
    5 replies    2017-01-08 19:44:13 +08:00
    Yinz
        1
    Yinz  
       Jan 7, 2017
    Python3 的求模运算里面用的是浮点数除法,超大奇数在浮点数除法时可能会丢失精度,导致结果错误。所以你把程序里面的超大整数套一层 Decimal 封装就好了。
    t/243078#r_2718109
    Chichele
        2
    Chichele  
       Jan 7, 2017
    md 你自己将输入值转成 float 了
    zonyitoo
        3
    zonyitoo  
       Jan 8, 2017
    primenumber=float(primenumbertext)

    闲得蛋疼?
    Kilerd
        4
    Kilerd  
       Jan 8, 2017 via iPhone
    质数还能是 float ???

    BTW ,质数判定算法建议用概率算法。(前段时间研究 1 个月的感受。)
    Bill1
        5
    Bill1  
    OP
       Jan 8, 2017
    @Kilerd
    @zonyitoo 和 int 效果相同呀
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