求指教这段 JS 代码是在做什么 - V2EX
MrSong0607

求指教这段 JS 代码是在做什么

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  •   MrSong0607 Jan 5, 2017 4290 views
    This topic created in 3413 days ago, the information mentioned may be changed or developed.

    如题:

    __d('BitMap', [], (function a(b, c, d, e, f, g) { var h = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-_'; function i() { 'use strict'; this.$BitMap1 = []; } i.prototype.set = function(l) { 'use strict'; this.$BitMap1[l] = 1; return this; }; i.prototype.toString = function() { 'use strict'; var l = []; for (var m = 0; m < this.$BitMap1.length; m++) l.push(this.$BitMap1[m] ? 1 : 0); return l.length ? k(l.join('')) : ''; }; i.prototype.toCompressedString = function() { 'use strict'; if (this.$BitMap1.length === 0) return ''; var l = [], m = 1, n = this.$BitMap1[0] || 0, o = n.toString(2); for (var p = 1; p < this.$BitMap1.length; p++) { var q = this.$BitMap1[p] || 0; if (q === n) { m++; } else { l.push(j(m)); n = q; m = 1; } } if (m) l.push(j(m)); return k(o + l.join('')); }; function j(l) { var m = l.toString(2), n = '0'.repeat(m.length - 1); return n + m; } function k(l) { var m = (l + '00000').match(/[01]{6}/g), n = ''; for (var o = 0; o < m.length; o++) n += h[parseInt(m[o], 2)]; return n; } f.exports = i; }), null); 
    Supplement 1    Jan 5, 2017
    没说清楚,只需要看 toCompressedString 这个函数的作用就好了,先谢过
    12 replies    2017-01-06 10:40:33 +08:00
    btjoker
        1
    btjoker  
       Jan 5, 2017
    base64 和图片相关
    你这代码没头没尾的, 让人猜?
    Nitroethane
        2
    Nitroethane  
       Jan 5, 2017 via Android
    函数的命名方式也是奇葩
    Nutlee
        3
    Nutlee  
       Jan 5, 2017
    这代码是压缩后的代码又格式化过的吧,建议看找源代码看啊 压缩会优化命名.....
    alwayshere
        4
    alwayshere  
       Jan 5, 2017
    @Nitroethane 这是压缩后的代码,函数命名全变了
    polun
        5
    polun  
       Jan 5, 2017
    感觉像压缩字符串的。
    rekulas
        6
    rekulas  
       Jan 5, 2017
    感觉像压缩二进制数据的,如果是,作者技术不错啊
    enenaaa
        7
    enenaaa  
       Jan 5, 2017
    用行程编码方式将二进制压缩成字符串, j 是具体的转换函数。
    enenaaa
        8
    enenaaa  
       Jan 5, 2017   1
    上面一条说得不太对, 应该是类似 base64 那样的转换编码。
    iEverX
        9
    iEverX  
       Jan 5, 2017   1
    bitmap 只有 0 和 1 , toCompressedString 里面的 l 记录了连续的 0 或者 1 的次数, j 函数想字符串前面加的 0 是为了能够区分连续的两个次数。 o + l.join('')是压缩后的 01 字符串
    davidzd
        10
    davidzd  
       Jan 5, 2017
    压缩字符串啊。。
    limerick
        11
    limerick  
       Jan 5, 2017   1
    toString 对二进制数据进行 base64 。 toCompressedString 对数据进行压缩处理然后进行 base64 。不过这个压缩处理要看压缩对象了,他这个处理方式是直接根据二进制中 0 , 1 的重复次数进行压缩。如果分布不是很连续感觉压缩之后打了很多。
    MrSong0607
        12
    MrSong0607  
    OP
       Jan 6, 2017
    @limerick
    @iEverX
    @enenaaa
    感谢各位
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