php 中如何将数字索引数组改为键名索引数组

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Array
(
[0] => stdClass Object
(
[id] => 1
[k] => AppName
[v] => 我是应用名称
[notes] => 应用名称
)
[1] => stdClass Object
(
[id] => 2
[k] => AppDescription
[v] => 我是应用描述
[notes] => 应用描述
)
[2] => stdClass Object
(
[id] => 3
[k] => AppVersion
[v] => 0.0.1
[notes] => 应用版本
)
)

如何变为下面这种:

Array
(
[AppName] => stdClass Object
(
[id] => 1
[k] => AppName
[v] => 我是应用名称
[notes] => 应用名称
)
[AppDescription] => stdClass Object
(
[id] => 2
[k] => AppDescription
[v] => 我是应用描述
[notes] => 应用描述
)
[AppVersion] => stdClass Object
(
[id] => 3
[k] => AppVersion
[v] => 0.0.1
[notes] => 应用版本
)
)
请大神赐教

Supplement 1 Jul 21, 2016

$SqlResult=(
[0]=>(stdClass)
k->'AppName',
v->'V2EX',
notes->'应用名称'
[1]=>(stdClass)
k->'AppSite',
v->'http://www.v2ex.com/',
notes->'应用网站'
[2]=>(stdClass)
k->'AppVersion',
v->100,
notes->'应用版本'
);

//array_column方法中貌似不能有对象,先转为数组
$SqlResultArray=json_decode(json_encode($SqlResult),TRUE);

//用$SqlResultArray的'k'作为键,'v'作为值生成新的键值数组
$Array=array_column($SqlResultArray,'v','k');

//输出$Array
print_r($Array);

Array
(
[AppName] => 'V2EX'
[AppSite] => 'http://www.v2ex.com/'
[AppVersion] => 100
)

13 replies 2016-07-22 09:27:50 +08:00