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def checkio(text):
t_count = 0
t_value = ''
text_lower = text.lower()
list = sorted(text_lower)
for i in list:
if i >= 'a' and i <= 'z':
if text.count(i) > t_count:
t_count=text.count(i)
t_value=i
print t_value
checkio("Aaaooo") #打印的是o
checkio("aaaooo") #打印的是a
为什么会出现这个情况,
text_lower = text.lower() 不是已经将所有的字符转为小写了吗?
t_count = 0
t_value = ''
text_lower = text.lower()
list = sorted(text_lower)
for i in list:
if i >= 'a' and i <= 'z':
if text.count(i) > t_count:
t_count=text.count(i)
t_value=i
print t_value
checkio("Aaaooo") #打印的是o
checkio("aaaooo") #打印的是a
为什么会出现这个情况,
text_lower = text.lower() 不是已经将所有的字符转为小写了吗?
4 replies 2014-08-04 20:48:41 +08:00
 | 1 flyee Aug 4, 2014 t_count=text.count(i) <==== text -> text_lower |
 | 2 insaneDream OP @flyee 可以细说一下吗 不太明白什么意思 |
 | 3 kamushin Aug 4, 2014  1 @makubx1 if i >= 'a' and i <= 'z': if text.count(i) > t_count: t_count=text.count(i) 这三句用的不还是没lower时候的text吗。。 |
| 4 insaneDream OP @kamushin 秒懂 感谢感谢!!! 原来自己瞎狗眼了 TAT |
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