为什么这段代码运行结果是这样的? 坑爹啊,为什么没有缩进…… 对于基础类型或者未定义__eq__方法的对象为什么可以直接调用右值的方法…… - V2EX
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xieys

为什么这段代码运行结果是这样的? 坑爹啊,为什么没有缩进…… 对于基础类型或者未定义__eq__方法的对象为什么可以直接调用右值的方法……

  •  
  •   xieys May 28, 2014 3062 views
    This topic created in 4353 days ago, the information mentioned may be changed or developed.
    class A(object):
    def __eq__(self,other):
    print 'A'

    class B(object):
    def __eq__(self, other):
    print 'B'

    class C(object):
    pass

    a=A()
    b=B()
    c=C()

    a==b
    b==a
    c==a
    a==c
    a=='123'
    '123'==a
    print '123'==c
    print c=='123'


    ---------------------------------------------
    A
    B
    A
    A
    A
    A
    False
    False
    3 replies    2014-05-31 18:04:13 +08:00
    mengzhuo
        1
    mengzhuo  
       May 28, 2014
    请用gist
    python 的 eq实现,当左对象没有__eq__时,调用另一个的__eq__
    hahastudio
        2
    hahastudio  
       May 28, 2014
    可以看这里 http://eev.ee/blog/2012/03/24/python-faq-equality/

    就你结果来看,对于新类,== 是这么判断的
    1. 左侧的类有没有自定义实现 __eq__?如果有,就调用left.__eq__(right)
    2. 右侧的类有没有自定义实现 __eq__?如果有,就调用right.__eq__(left)

    其实你可以试试C继承A,重写__eq__,a==c会print 'C',根据blog,可以追加:
    0. 右侧的类是左侧的类的子类,并且重写了__eq__,调用right.__eq__(left)
    3. 都没有?尝试使用__cmp__重复上述过程
    4. 尝试调用object.__eq__(a, b)
    konakona
        3
    konakona  
       May 31, 2014
    用IDE格式化一下...
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