V2EX samuel
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嗷呜
Feb 13, 2017
干嘛用的?
May 4, 2014
Feb 15, 2014
samuel
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samuel

  Breeze.cash / Fullstack Engineer
V2EX member #132, joined on 2010-04-26 16:06:59 +08:00
samuel's recent replies
> 智齿可能导致或加剧夜间磨牙症(磨牙),因为其萌出时可能导致牙齿咬合不齐,引起不适和颌部肌肉紧张,从而引发夜间磨牙行为

楼主可以看看是不是有智齿要拔,我拔了智齿就再没磨过了
真有趣!送出一点 V2EX 聊表心意
@zuosiruan 这个目前还没有证据吧
楼主的分析有一个明显的漏洞:既然是讨论纹身和女孩好坏在概率上的分布,我们不能光看 P坏女孩|纹身),还要看 P(坏女孩|不纹身)。先不说楼主假设的数据是否合理,以那个数据为例,P(坏女孩|不纹身)仅有 5.8%,对比各种不同择偶标准,遇到坏女孩的概率,见如下表格:

|择偶标准 |坏女孩概率|
|只找有纹身的| 35.7% |
|只找没纹身的| 5.8% |
|都可 | 10% |
@boogoogle 微信聊?
我 8G 的老 mac 用到飞起,原来是因为我有见不了浏览器开太多 tab 的强迫症 LOL
@sky96111 其实根源是手机厂商的宣传故意偷换概念,忽悠不知道区分 RAM 和闪存的普通用户,毕竟 PC 时代教会了他们内存越快机器性能越好
看题意估计时间是不可以取小数的,直接用优先队列来维护衣服的湿度变化,就是时间计算和状态更新上有点小 trick ,关键点是不要 每次迭代都更新全部衣服的湿度,那会带来 N^2 的复杂度

差不多是这个样子,感觉复杂度应该是 O(N),因为每次都尽可能的把当前衣服烘干,所以一衣服最多能有机会被烘两次

from queue import PriorityQueue
import math

def dry(N, A, B, clothes):
q = PriorityQueue()

for h in clothes:
q.put(-h)

elapsed = 0

while True:
head = q.get() * -1
if elapsed * A > head:
break
delta = max(int(math.floor((head - A * elapsed * 1.0) / (A+B))), 1)
elapsed += delta
new_head = head - delta * B
q.put(-new_head)

return elapsed
Oct 21, 2021
Replied to a topic by EyebrowsWhite Pixel 想问下有 Pixel 用户吗?
Pixel 3,香
Pixel 4,一般香,主要是手感不好,硌手
Pixel 5,香
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