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passport-signup.html

function sendVerify (el, data ) {
var url = el.href;
var textCOnt= el.getElement ('span span');
el.addClass ('disabled');
textCont.innerHTML = el.get ('text') + '(<i>0</i>)';
var cd = new countdown (textCont.getElement ('i'), {
start: 120,
secondOnly: true,
callback: function (e ) {
el.removeClass ('disabled');
textCont.innerHTML = '重发验证码';
}
});
Query.send (url, el, data, function (rs ) {
if (rs.error ) {
changeCode (Module.element (modname, 'img.auto-change-verify-handle'));
cd.stop ();
el.removeClass ('disabled');
textCont.innerHTML = '重发验证码';
}
});
}

2014-12-24 13:52:25 +08:00

回复了 esplendo 创建的主题推广乐享圣诞，喜迎新年抽奖活动（截止日期： 2015.1.2）

75918

2014-11-28 16:55:51 +08:00

回复了 esplendo 创建的主题推广有你，真好！ Think In Cloud 感恩抽奖活动（截止日期： 12.3）

2012-10-17 12:18:27 +08:00

回复了 enj0y 创建的主题程序员 JS求助

按你的思路简单改了下:

function sub_html_restr(str, num)
{
var reg = new RegExp( '<[^>]+>' , 'g' );
var rt, rts = [], indexs = [], tstr, endstr, rstr, sstr, endtag, rtstr, restr;

//提取所有的html标签和标签在字符串中的位置
while ( ( rt = reg.exec(str) ) != null )
{
rts.push(rt[0]);
indexs.push(rt['index']);
}

//删除字符串中所有的html标签
tstr = str.replace(reg, '');
//对剩余的纯字符串进行substr

sstr = tstr.substr(num, tstr.length);
tstr = tstr.substr(0, num);

//判断有没有把实体腰斩，如果有腰斩的就再接上
endstr = (/&[^&]*$/.exec(tstr) || '');
if ( endstr !== '' ) endstr += '' + (/^[^;]*;/.exec(sstr) || '');
if (/^(&\w{1,10};|&#\d+;)$/.test(endstr))
{
rtstr = tstr.replace(/&[^&]*$/, endstr);
}
else
{
rtstr = tstr;
}

//把html标签放回到截断完毕的字符串中，当然有的html标签这时候已经无家可归了

var index = 0;

for (var i = 0; i < rts.length; i ++)
{
index = indexs[i];
if (rtstr.length >= index)
{
rtstr = rtstr.substr(0, index) + rts[i] + rtstr.substr(index, rtstr.length);
}
else
{
break;
}
}

restr = str.substr(rtstr.length,str.length)

//把闭合的标签全部删除
tstr = restr;
rstr = '';
while ( rstr != tstr )
{
rstr = tstr;
tstr = tstr.replace(/<[^\/][^>]*>[^<]*<\/[^>]+>/g, '').replace(/<[^>]+ \/>/g, '');
}

var lastindex = i ;
var endreg = new RegExp('<\/([^>]+)>', 'g');
var tagreg = new RegExp('<?([^ >]+)[ ]?[^ ]*>?');
//如果存在没有闭合的标签，从切断的标签里找上半身
while( (endrt = endreg.exec(tstr))!=null){
for(var i = lastindex-1;i>-1;i--){
if(tagreg.exec(rts[i])[1]==tagreg.exec(endrt[1])[1]){
restr = rts[i] + restr;
lastindex = i;
break;
}
}
}
return restr;
}

</script>
<script>
document.writeln('<textarea cols="100" rows="10">');
document.writeln(sub_html_restr('<xx><oo>嵌套标签截断测试</oo><fk><test>lala</test></fk></xx>', 5));
document.writeln(sub_html_restr('正常字符串测试', 5));
document.writeln(sub_html_restr('<xx>带标签的字符串截断</xx>', 5));
document.writeln(sub_html_restr('<xx><oo>嵌套标签截断测试</oo><fk>lala</fk></xx>', 5));
document.writeln(sub_html_restr('<xx><oo>嵌套标签<img src="http://www.google.com/logo.gif" />截断测试</oo></xx>', 5));
document.writeln(sub_html_restr('<xx><oo>实体截断 测试测试</oo></xx>', 5));
document.writeln(sub_html_restr('<xx><oo>实体截断 测试测试</oo></xx>', 5));
document.writeln('</textarea>');
</script>

但是,这里有个bug,你没有存储标签的配对,所以遇到document.writeln(sub_html_restr('<xx><oo><oo a=1></oo>截断测试测试</oo></xx>', 5));这种就没办法了.