V2EX hardness assumption

Hardness Assumption

释义 Definition

(密码学/计算复杂性)困难性假设:指一种广泛使用的前提某类计算问题在现实可行的时间与资源内“很难”被解决(例如对任意高效算法都难以在合理概率下成功)。密码系统的安全性证明常把“攻破系统”归约为“能解决该困难问题”,从而基于该假设成立来论证安全。
(在不同语境中也可泛指“某个问题很难”的假设,但最常见于现代密码学。)

发音 Pronunciation (IPA)

/hrdns smpn/

例句 Examples

The security of this scheme relies on a hardness assumption.
该方案的安全性依赖于一个困难性假设。

Under the discrete-log hardness assumption, an efficient adversary should not be able to compute the secret key from public data with non-negligible probability.
在离散对数困难性假设下,高效的攻击者不应能以不可忽略的概率仅凭公开数据计算出密钥。

词源与背景 Etymology & Notes

hardness 来自 hard(“难的、硬的”)+ 名词后缀 -ness(表示性质),意为“困难性/难度”;assumption 来自拉丁语系词源,表示“假设、前提”。在密学中,这个短语用于把安全建立在某个被认为计算上难解的“基础问题”之上(如大数分解、离散对数、格问题等)。

相关词 Related Words

文献与作品 Literary / Notable Works

  • Introduction to Modern Cryptography(Katz & Lindell):大量使用并讲解各类 hardness assumption 与安全归约证明。
  • A Graduate Course in Applied Cryptography(Boneh & Shoup):以教学方式系统呈现常见困难性假设(如离散对数、CDH/DDH 等)。
  • “Probabilistic Encryption” (Goldwasser & Micali, 1982/1984):早期将安全性与计算困难性假设紧密结合的代表性工作。
  • “New Directions in Cryptography” (Diffie & Hellman, 1976):公钥密码思想的重要起点,相关安全讨论常依赖困难性假设。
  • “A Method for Obtaining Digital Signatures and Public-Key Cryptosystems” (Rivest, Shamir, Adleman, 1978):RSA 的提出与后续安全讨论通常依赖分解困难性假设的相关形式。
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